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Last edited: 2011-11-03 09:44 AM Readings for this section.Petrucci: Section 10-7 Valence Shell Electron Pair Repulsion TheoryMolecular GeometriesNOTE All the coloured pictures have java-enabled rotatable models available. Click on the image to open the page containing the java applet. Experimental evidence clearly shows us that the Lewis Model of molecular bonding, while having it's merits is far from complete. Take for example the molecule Chlorofluoromethane (CH2FCl) If we draw the Lewis Dot Structure for this molecule, we get one of two possibilities:
These structures seem to show that there are two different versions of this molecule, one in which the chlorine is adjacent to the fluorine and one where it is across from it. Experimental evidence shows us that there is only one molecule with the formula CH2FCl. At the same time evidence points to the fact that the molecule CH2FCl has two distinct forms with different physical properties (optical properties). There must be further theories that can explain these observations.
Can you superimpose these?
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| Electron Pairs | e– pair (domain) Geometry | e– pair diagram |
|---|---|---|
| 2 | Linear |
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| 3 | Trigonal planar |
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| 4 | Tetrahedral |
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| 5 | Trigonal bipyramidal |
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| 6 | Octahedral |
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We'll now go through a set of example molecules and/or ions and discuss their geometries. It is important to note that the shape of the molecules as we discuss them here is not always the same as the electron domain geometries described above.
We will consider the molecular shapes, starting with the simplest and working up to the more complicated examples. In addition, I'll mention a classification system which may be helpful in counting electron domains used herein.
For example, methane CH4 is an AX4 molecule while ammonia NH3 is an AX3E molecule. Both of these molecules have four electron domains and hence would have a tetrahedral domain geometry as listed above. However, the shape of the molecules are not the same as we will see below.
BeCl2 LINEAR This molecule is linear. The Be does not fill its octet shell in this situation. To do so would put a large negative charge on it and a positive charge on the Chlorine atoms. This would simply not happen since Cl is so much more electronegative than Be.
BF3 ![]()
Trigonal Planar shape
4 electron pairs
CH4 AX4 tetrahedral NH3 ![]()
AX3E trigonal pyramidal H2O AX2E2 bent or angular HF AX1E3
or just
AXE3linear
Note that in all these cases, the electron-domain geometry is tetrahedral. However, the molecular shape is not always so. In the case of CH4, the molecule is actually tetrahedral in shape with a perfect Tetrahedral angle of 109.5º. The next two examples have lone pairs which occupy a larger domain volume (push more on the bonding pairs) and reduce the bond angle to less than 109.5º. The last case, HF, is simply a liner diatomic molecule. There is no bond angle.
PCl5 AX5 trigonal bipyramidal SF4 ![]()
AX4E See Saw
or
disphenoidalClF3 ![]()
AX3E2 T-shaped XeF2 AX2E3 Linear
In these cases, the electron-domain geometry is always trigonal bipyramidal. However, only the first molecule is that shape with the ideal angles of 90 and 120 degrees for the axial and equatorial bonds, respectively.
In the case of SF4, there is one lone pair and four bonding pairs. The lone pair will preferentially locate itself in an equatorial position since that position has only two other pairs of electrons within 90 degrees while an axial position would have three. Thus, the molecular would be see-saw shaped or the more technically correct name, disphenoidal. The bond angles would be less than the ideal angles of 90 and 120 degrees.
ClF3 has two lone pairs and they both locate themselves in equatorial positions for the same reasons as described in the previous case. This molecule is T-shaped with bond angles of less than 90 degrees.
SF6 AX6 Octahedral ClF5 AX5E Square Pyramidal
XeF4 AX4E2 Square Planar
In all these cases, the electron-domain geometry is octahedral and in the case of SF6, so is the shape. The molecule ClF5 has one lone pair and five bonding pairs but since all positions in the octahedral geometry are equivalent, it doesn't matter which position the lone pair takes. I drew it on the bottom position here for visual effect. In the case of XeF4, the two lone pairs will locate themselves on opposite sides of the square planar molecule. In the case of the XeF4 molecule, the lone pairs will orient themselves in a square plane and the molecule will be linear in shape.