This "molecular orbital diagram" in this exercise is a bit different from those of other exercises and, strictly speaking, is not really a molecular orbital diagram. The orbital energies for nitric oxide derive from ab initio calculations.
Before examining this diagram, careful examine the molecular orbitals for carbon monoxide. Nitric oxide differs from carbon monoxide in that it has an unpaired electron. In this particular case, the presence of a single electron in an orbital destroys the symmetry of the molecule and the usual degeneracy for the pi bonding orbitals and pi antibonding orbitals is destroyed.
Draw the Lewis structure for nitric oxide and use it to answer the following questions.
Answer these same questions using the molecular orbital diagram.